(4t-7)^2-7(4t-7)+5=0

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Solution for (4t-7)^2-7(4t-7)+5=0 equation: 



(4t-7)^2-7(4t-7)+5=0

We multiply parentheses

(4t-7)^2-28t+49+5=0

We add all the numbers together, and all the variables

-28t+(4t-7)^2+54=0

We move all terms containing t to the left, all other terms to the right

-28t+(4t-7)^2=-54

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